Basic Whole number tutorial
Modul pengajaran dan pembelajaran
Mathematics form 1
Subject : Mathematics Form 1
Learning Objective : Whole Number
Learning Outcomes :
1. Read and write whole numbers.
2. Understand the place value and the value of digits.
3. Round off a whole numbers.
4. Perform addition, subtraction, multiplication and division of whole numbers.
5. Perform computations of combined operations including the use of brackets.
6. Solve problems involving whole numbers.
1.1 Whole Numbers
Definition : Whole numbers are any number made from the ten digits numbering system of 0, 1, 2, 3, 4, 5, 6, 7, 8 and 9.
Write the following numbers in words.
1. 97 = ninety  seven
2. 342 = three hundred and forty  two
3. 1 512 = one thousand five hundred and twelve
4. 70 678 = seventy thousand six hundred and seventy  eight
5. 200 924 = two hundred thousand nine hundred and twenty  four
Write the following numbers in figures.
1. fifty  nine = 59
2. seven hundred and ten = 710
3. eight thousand six hundred and fourteen = 8 614
4. eleven thousand three hundred and twenty  five = 11 325
5. four hundred and sixty – one thousand three hundred and ninety  two= 461 392
State the place value and the value of underlined digit
1. 9 056 place value = thousands value of digit = 9 000
2. 236 890 place value = ten thousands value of digit = 30 000
3. 47 802 place value = hundreds value of digit = 800
4. 1 279 603 place value = millions value of digit = 1 000 000
Rounding off whole numbers
 If the digit to the right of the rounded off number is
a) less than 5, retain the digit, replace all the right digits with zero
b) 5 or greater than 5, add 1 to the digit, replace the right digits with zero
1. Round off 6 572 to the nearest
a) tens = 6 572 = 6 570
b) hundreds = 6 572 = 6 600
c) thousands = 6 572 = 7 000
2. Round off the followings to the correct place values
1.2 Addition and Subtraction of Whole Numbers
Addition of whole numbers
 The process of finding the total of numbers.
 Keywords – sum, add, plus, total
 Symbol “ + ”
Find the sum of the followings
1. 147 + 297 = 444
2. 1 530 + 197 = 1 727
3. 67 915 + 206 + 38 = 68 159
4. 46 275 + 396 486 + 5 873 = 448 634
5. 17 308 + 891 + 45 + 176 401 = 194 645
Problem solving involving addition of whole numbers
1. Last Christmas, Mary Anne received RM 125 from her father, RM 87 from her mother and RM 62 from her sister. Find the total amount of money she received.
RM (125 + 87 + 62 ) = RM 274
Therefore the total amount of money Mary Anne received is RM 274
2. The table shows Ali’s marks for Maths test for Feb, March and April. What are his total marks for the three months?
89 + 64 + 97 = 250
Therefore the total marks for the three months are 250 marks
3. In a Maths quiz, Abu scores 85 points, Kumar scores 7 points more than Abu and Suzy gets 6 points less than Kumar. Find the total scores they get?
Abu = 85 points
Kumar = 85 + 7 = 92 points
Suzy = 92 – 6 = 86 points
85 + 92 + 86 = 236 points
Therefore the total scores they get is 236 points
Subtraction of whole numbers
 The process of finding difference between two numbers.
 Keywords – difference, minus, subtract
 Symbol “  ”
Do the following subtraction.
1. 978  253 = 725
2. 4 130 – 1 572 = 2 558
3. 793  89 = 704
4. 132 012 – 6 718 – 56 137 = 125 294 – 56 137 = 69 157
5. 9 352 – 7 001 – 999 = 2 351 – 999 = 1 352
Problem solving involving subtraction of whole numbers
1. There are 2 957 students in SMK Berjaya and 1 379 of them are girls. Find the number of boys.
2 957 – 1 379 = 1 578
Therefore the number of boys in SMK Berjaya is 1 578 students
2. Mr. Tiong donated RM 121 365 to a school. The school used RM 76 450 to buy 20 computers. How much money is left?
RM ( 121 365 – 76 450) = RM 44 915
Therefore the money left is RM 44 915
3. There were 32 408 exercise books in the school bookshop in the beginning of the year. At the end of year only 3 729 books were unsold. Find the number of exercise books which were sold during the year.
32 408 – 3 729 = 28 679
Therefore the number of exercise books sold during the year were 28 679 books.
1.3 Multiplication and Division of Whole Numbers
Multiplication of whole numbers
 The process of repeated addition.
 Keywords – multiply, times, product
 Symbol “ × ”
Find the product of the followings.
1. 147 × 23 = 3 381
2. 69 × 82 = 5 658
3. 336 × 8 × 125 = 2 688 × 125 = 336 000
4. 72 × 11 × 49 = 792 x 49 = 38 808
Problem solving involving multiplication of whole numbers
1. Jamie can type 42 words in 1 minute. How many words can she type in 38 minutes?.
42 words x 38 minutes = 1 596 words
Therefore Jamie can type 1 596 words in 38 minutes.
2. Amy’s salary for a month is RM 1 355 and Muthu’s salary is 4 times more than Amy. Calculate Muthu’s salary.
RM 1 355 x 4 = RM 5 420
Therefore Muthu’s salary is RM 5 420
3. A basket contains 37 durians. Pak Mat bought 15 baskets of durians. If each durian costs RM 2, find the total cost of his purchase.
37 durians x 15 baskets X RM 2 = 555 x RM 2 = RM 1 110
Therefore the total cost of Pak M
at’s purchase is RM 1 110
Division of whole numbers
 The process of putting things into equal groups.

Keywords – divide, quotient
Do the followings divisions.
1. 2 292 ÷ 4 = 573
2. 986 ÷ 6 = 164 remainder 2
3. 3 868 ÷ 14 = 276 remainder 4
4. 11 648 ÷ 56 = 208
5. 10 076 ÷ 25 = 403 remainder 1
Problem solving involving division of whole numbers
1. 672 sweets are shared equally among 42 students. How many sweet does each student get?
672 ÷ 42 = 16 sweets
Therefore each student will get 16 sweets.
2. The donation of RM 21 100 is divided among 20 flood victims. How much money does each flood victims will get.
RM 21 100 ÷ 20 = RM 1 055
Therefore each flood victim will get RM 1 055
3. Mak Siti fried 650 pieces of pisang goring and puts 12 pieces of pisang goreng into each plastic bag.
a) How many plastic bag did she used?
b) How many pieces of pisang goring were left?
650 ÷ 12 = 54 remainder 2
Therefore a) Mak Siti used 54 pieces of plastic bags
b) There were 2 pieces of pisang goring left.
1.4 Combined Operations of Whole Numbers
 Involving more than one operation such as addition, subtraction, multiplication, division and the use of brackets.
Tips a) BODMAS Rule  B Bracket ( )
O
D Division ÷
M Multiplication x
A Addition +
S Subtraction 
b) for operation x and ÷, operation + and  , do from left to right
Calculate the followings
1. 572 + 200 – 99 = 772 – 99
= 673
2. 8 852 – 3 214 + 731 = 5638 + 731
= 6 369
3. 36 x 8 ÷ 4 = 288 ÷ 4
= 72
4. 119 ÷ 7 x 16 = 17 x 16
= 272
5. 83 + ( 12 – 7 ) x 5 = 83 + 5 x 5
= 83 + 25
= 108
6. 172 – 92 ÷ 4 + 36 = 172 – 23 + 36
= 149 + 36
= 185
7. 4 ( 72 – 28 ) + 253 = 4 ( 44 ) + 253
= 176 + 253
= 429
8. 136 + 64 ÷ 4 ( 9 – 7 ) = 136 + 64 ÷ 4 ( 2 )
= 136 + 64 ÷ 8
= 136 + 8
= 144
9. ( 40 + 56 ) x 3 ÷ ( 4 + 12 ) = 96 x 3 ÷ 16
= 288 ÷ 16
= 18
Problem solving involving combined operations of whole numbers
1. The bus fare from Bintulu to Sibu is RM 32 for an adult and RM 18 for a child. A family consist of 3 adults and 5 children wish to travel to Bintulu to Sibu by bus. Calculate the total fare paid by the family.
( RM 32 x 3 adults) + ( RM 18 x 5 children )
= RM 96 + RM 90
= RM 186
Therefore the total fare paid by the family is RM 186
2. Mr. Chua bought 16 story books and 19 colouring books for RM 242. If each story book costs RM 8, find the cost of one colouring book.
( RM 242 – 16 x RM 8 ) ÷ 19
= ( RM 242 – RM 128 ) ÷ 19
= RM 114 ÷ 19
= RM 6
Therefore the cost of one colouring book is RM 6
Summative Exercises : Chapter 1
1. 72 + 4 – 35 ÷ 5
2. 32 + 72 ÷ 9 x 3 – 12
3. 56 ÷ 8 + 6 x 7 – 34
4. 4 x ( 8 ÷ 2 ) – 3 + ( 12 – 8 )
5. 64 ÷ 4 x ( 2 + 6 )
6. ( 36 – 29 ) x ( 12 + 2 x 8 ) ÷ 4
7. 3 ( 8 + 4 – 9 ) + ( 24 ÷ 2 x 3 )
8. 220 – 52 ÷ 4 + 16
9. ( 12 + 6 ÷ 3 ) + 20 x 6 ( 19 – 3 )
10. 2 235 – 3 ( 645 ÷ 5 ) + 100
Problem Solving
1. The cost of 1 kg of anchovies and 1 kg of cuttlefish are RM3 and RM6 respectively. Mrs. Chong bought 4kg of anchovies and 3 kg of cuttlefish. Calculate the amount of money she has to pay.
2. A shopkeeper sold 38 shirts last month. He sold 4 times as many shirts this month compared to the number sold last month. How many shirts did he sell this month?
3. Zain had 37 sweets. After giving some to his two brothers, he had 25 sweets left. If each of his brother received the same number of sweets, how many sweets did each of his brother receive?
End of this Basic whole number tutorial
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